The scores of a batsman in the last 10 innings were 10, 0, 25, 9, 24, 81, 28, 2, 1, and 59. What is the probability that he will score more than 30 runs in his next innings (in decimal)?

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Solution

The batsman’s score in the previous 10 innings is 10, 0, 25, 9, 24, 81, 28, 2, 1, and 59.

The number of times the batsman scored above 30 = 2

The total number of innings he played = 10

Therefore, the probability that he will score more than 30 in the next match is $= \frac{Number of favourable outcomes}{Total number of possible outcomes}$

$= \frac{2}{10}$ $= \frac{1}{5}$ $= 0.2$

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The scores of a batsman in the last 10 innings were 10, 0, 25, 9, 24, 81, 28, 2, 1, and 59. What is the probability that he will score more than 30 runs in his next innings (in decimal)? __

The scores of a batsman in the last 10 innings were 10, 0, 25, 9, 24, 81, 28, 2, 1, and 59. What is the probability that he will score more than 30 runs in his next innings (in decimal)?

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