The scores of Jimmy's soccer match were recorded to be:
3, 7, 13, 14, 6, 7, 9, 8, 10, 5, 6, 6, 10, 12.
What is the median score?

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7.5

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8.5

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Solution

The correct option is B 7.5
Median is the middle value of a numerically ordered data set.

Arranging the scores in ascending order we get:
3, 5, 6, 6, 6, 7, 7, 8, 9, 10, 10, 12, 13, 14.

Since the total number of data points is even, the median is the mean of the two central values of the data set arranged in ascending order.

The mean of the two central numbers would be: $\frac{7 + 8}{2}$ = 7.5

Thus, the median of the given data set is 7.5.

Hence, the median score is 7.5.

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Similar questions

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17, 2, 7, 27, 15, 5, 14, 8, 10, 24, 48, 10, 8, 7, 18, 28
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Q. A football player scored the following number of goals in the

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Is it the correct answer and why?

Q. In a football tournament, scores of a team in

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matches are as follows:

$9$	$0$	$1$	$2$	$3$	$2$
$3$	$4$	$6$	$1$	$7$	$3$

What is the median score of the team?

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

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The scores of Jimmy's soccer match were recorded to be: 3, 7, 13, 14, 6, 7, 9, 8, 10, 5, 6, 6, 10, 12. What is the median score?

The scores of Jimmy's soccer match were recorded to be:
3, 7, 13, 14, 6, 7, 9, 8, 10, 5, 6, 6, 10, 12.
What is the median score?