Question

The scores of two golfers for 10 rounds each are
A:58, 59, 60, 54, 65, 66, 52, 75, 69, 52
B:84, 56, 92, 65, 86, 78, 44, 54, 78, 68
B is a more consistent player than A . If this is true enter 1, else enter 0.

Answer 1

Golfer $A$
Mean $\overline{X}=\frac{\sum x}{N}=\frac{610}{10}=61$
S.D.$=\sqrt{\frac{\sum {(x-\overline{x})}^2}{N}}$
$=\sqrt{\frac{526}{10}}=\sqrt{52.6}=7.25$
$C.V=$$\frac{S.D.}{x}\times 100=\frac{7.25}{61}\times 100=11.88$%
Golfer$B$
Mean$\overline{y}=\frac{\sum y}{N}=\frac{705}{10}=70.5$
S.D.$=\sqrt{\frac{\sum {(y-\overline{y})}^2}{N}}$
$=\sqrt{\frac{2218.50}{10}}=\sqrt{221.85}=14.89$
$C.V=$$\frac{S.D.}{y}\times 100=\frac{14.89}{70.5}\times 100=21.12$%
$\therefore$Golfer$A$ is more consistent.