The second electron gain enthalpies $(i n k J {m o l}^{- 1})$ of oxygen and sulphur respectively are :

780, + 590

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590, + 780

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+590, 780

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+780, + 590

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Solution

The correct option is D +780, + 590
Second electron gain enthalpy of oxygen is greater than that of sulphur as oxygen is small sized and it is more difficut to add one more $e^{-}$ to it

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O_{2} (g)

O^{2 -} (g)

639 {kJ mol}^{- 1}

O^{-} (g)

141 {kJ mol}^{- 1}

780

210

\frac{tan 35^{0}}{cot 55^{0}} + \frac{cot 78^{0}}{tan 12^{0}} - 1

{({(\frac{4}{7})}^{8})}^{0}

P = 780

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