The second equation of motion in rotatory motion is

S = u t + \frac{a t^{2}}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

θ = ω_{1} t + \frac{α t^{2}}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

ω_{2}^{2} = ω_{1}^{2} + 2 α θ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

ω_{2} = ω_{1} + α t

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $θ = ω_{1} t + \frac{α t^{2}}{2}$
$S = u t + \frac{a t^{2}}{2}$ is the second equation of linear motion.
Substituting analogous physical quantities of rotatory/circular motion in this we get $θ = ω_{1} t + \frac{1}{2} α t^{2}$
This is the second equation of circular motion

Suggest Corrections

Similar questions

S = u t + 1 / 2 {a t}^{2}, S

20 derive the second equation of motion S is equal to UT Plus 1/2 at 2 numerically

(1 + ω) (1 + ω^{2}) (1 + ω^{4}) (1 + ω^{8})

(1 - ω + ω^{2})^{7} + (1 + ω - ω^{2})^{7}

(1 - ω) (1 - ω^{2}) (1 - ω^{4}) (1 - ω^{8})

(1 - ω + ω^{2}) (1 - ω^{2} + ω^{4})

\begin{matrix} Column I & Column II a) & Velocity at t = 0 of a particle following & p) & α equation x = u (t - 8) + α (t - 2)^{2} b) & Acceleration of a particle moving according to equation & q) & 2 α x = 4 (t - 5) + α (t - 2)^{2} at t = 0 c) & Velocity of the particle moving according to equation & r) & u x = u t + 5 α t^{2} l n (1 + \frac{t}{2}) + α t^{2} at t = 0 d) & Acceleration of the particle moving according to the equation & s) & u - 4 α x = u t + 5 α t^{2} l n (1 + \frac{t}{2}) + α t^{2} at t = 0 \end{matrix}

Join BYJU'S Learning Program