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Question

THe second excitation potential of a given atom is 12.08V. The ionisation potential must be

A. 12.08V

B. 13.6V

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Solution

when electron jumps from n=1 to the another energy level n=3 the corresponding energy is called 2nd excitation potential energy and corresponding potential is called 2nd excitation potential.
2nd excitation energy = -1.5ev-(13.6ev)=12.1ev
2nd excitation potential = 12.1v

ionization potential energy is defined as the minimum energy required in ev to excite a neutral atom to its ionized state i.e it is the minimum energy required in ev to excite an electron from n=1 to infinity.
ionization energy = 0-(-13.6ev)=13.6ev
ionization potential = 13.6v

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