THe second excitation potential of a given atom is 12.08V. The ionisation potential must be
A. 12.08V
B. 13.6V
Open in App
Solution
when electron jumps from n=1 to the another energy level n=3 the corresponding energy is called 2nd excitation potential energy and corresponding potential is called 2nd excitation potential. 2nd excitation energy = -1.5ev-(13.6ev)=12.1ev 2nd excitation potential = 12.1v
ionization potential energy is defined as the minimum energy required in ev to excite a neutral atom to its ionized state i.e it is the minimum energy required in ev to excite an electron from n=1 to infinity. ionization energy = 0-(-13.6ev)=13.6ev ionization potential = 13.6v