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Question

The second, first and third term of an arithmetic progression form a geometric progression in that order. Which of the following can be the common ratio of the geometric progression?

A
2
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B
3
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C
2
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D
2
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Solution

The correct option is C 2
First term of AP is =a
Second term =a+d
Third term =a+2d
So the first three terms of GP are a,a+d,a+2d
In a geometric progression, there is a common ratio. So the ratio of the second term to the first term is equal to the ratio of the third term to the second term. So
a+da=a+2da+d
a2+2ad+d2=a2+2ad
d2=0
d=2
The common ratio of the geometric progression, r, is equal to(a+d)a
if d=2
thenr=a+2a=a2a=2

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