The second homologue of alkyne is :

C H

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C_{2} H_{2}

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C_{2} H_{4}

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C_{3} H_{4}

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Solution

The correct option is D $C_{3} H_{4}$
The second member of the alkyne series is propyne because methyne does not exist as it cannot have triple bond with single carbon atom so the first member of alkyne series is ethyne and second member is propyne.

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Similar questions

Q. Homologue of

C_{3} H_{4}

is :

Classify the following compounds as alkanes, alkenes and alkynes. [3 MARKS]

$C_{5} H_{1} 2$ , $C_{2} H_{4}$ , $C_{3} H_{4}$ , $C_{3} H_{8}$ , $C_{4} H_{8}$ , $C_{5} H_{8}$

Q. Compare the

C H

bond strength in

C_{2} H_{6}, C_{2} H_{4}

and

C_{2} H_{2}

Q. (a) What is the general formula of alkenes? Identify the alkenes from the following:
C₂H₆, C₂H₄, C₃H₄, C₂H₂, C₃H₆
(b) Which of the following can give addition reactions?
C₂H₆, C₃H₈, C₃H₆, C₂H₂, CH₄
Give reason for your choice.

Complete and balance the following equations. State the conditions wherever necessary.
(a) $C H \equiv C H + H_{2} \to$ ______ $+ H_{2} \to$ _________
(b) $C_{2} H_{4} + B r_{2} \to$ _________
(c) $C_{2} H_{4} + H C l \to$ _________
(d) $C a C_{2} + H_{2} O \to$ _________
(e) $C_{2} H_{2} + B r_{2} \to$ _________
(f) $C_{2} H_{5} O H [O] - ---- \to K_{2} C r_{2} O_{7}$ _________

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The second homologue of alkyne is :

The correct option is D C3H4The second member of the alkyne series is propyne because methyne does not exist as it cannot have triple bond with single carbon atom so the first member of alkyne series is ethyne and second member is propyne.

The correct option is D $C_{3} H_{4}$
The second member of the alkyne series is propyne because methyne does not exist as it cannot have triple bond with single carbon atom so the first member of alkyne series is ethyne and second member is propyne.