The second ioniosation energy of $N$ and $O$ in electron volt are respectively given by:

29, 29

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34, 34

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29, 34

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34, 29

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Solution

The correct option is D $29, 34$
Oxygen after loss of an electron attains stable half filled configuration $[H e]^{2} 2 s^{2} 2 p^{3}$ . Therefore, second ionization potential of oxygen is high and greater than second ionization potential of nitrogen.

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