The second ionisation potentials in electron volts of oxygen and fluorine atoms are respectively given by:
A
35.1, 38.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
38.3, 38.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
38.3, 35.1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
35.1, 35.1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A 38.3, 35.1 The second ionization potentials of oxygen and fluorine atoms are 38.3 eV and 35.1 eV respectively.
The electronic configuration of O+ ion is 1s22s22p3 whereas that of O2+ ion is 1s22s22p2. Thus, during ionization, the stable configuration of half filled 2p orbital is broken. This requires high energy.
The electronic configuration of F+ ion is 1s22s22p4 whereas that of F2+ ion is 1s22s22p3. Thus, during ionization, the stable configuration of half filled 2p orbital is formed. This requires less energy.