Question

The second order Bragg diffraction of X-rays with $\lambda =1.00\mathring{A}$ from a set of parallel planes in a metal occurs at an angle of ${60}^o$. The distance between the scattering planes in the crystal is (in $\mathring{A}$) :

• A. $0.577$
• B. $1.00$
• C. $2.00$
• D. $1.15$

Answer 1

The correct option is D $1.15$

The Bragg's equation is $2dsin\theta =n\lambda$

d is the distance between the scattering planes in the crystal.

$\theta$ is the angle of diffraction.

n is the order of diffraction.

$\lambda$ is the wavelength of X rays.

$2d\times sin{60}^0=2\times 1A^o$

$d=1.15A^o$

The distance between the scattering planes in the crystal is $d=1.15A^o$