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Question
The second order Bragg diffraction of x-rays with λ=1.00 ∘A from a set of parallel planes in metal occurs at an angle 60∘. The distance between the scattering planes in the crystal is
The second order Bragg diffraction of x-rays with λ=1.00 ∘A from a set of parallel planes in metal occurs at an angle 60∘. The distance between the scattering planes in the crystal is
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Solution
The correct option is D 1.15 ∘A
Bragg's Equation:
nλ=2d sin θ
Now, n=2,λ=1.00 ∘A,θ=60∘,d=?⇒d=1sin 60∘=2√3=1.15 ∘A
1.15 ∘A
Bragg's Equation:
nλ=2d sin θ
Now, n=2,λ=1.00 ∘A,θ=60∘,d=?⇒d=1sin 60∘=2√3=1.15 ∘A
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