The second order Bragg diffraction of X-rays with l =1.0 A⁰froma set of parallel planes in a metal occurs at an angle of 60⁰.The distance between the scattering planes in the crystal is

Q. The second order Bragg's diffraction of rays with

λ

= 1A from a set of parallel planes in a metal occurs at an angle of

60^{\circ}

The distance between the scattering planes in the crystal is

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The second order Bragg diffrction of X−rays with λ=1.00A∘ from a set of parallel planes in a metal occurs at an angle 60∘. The distance between the scattering planes in the crystal is

The correct option is D 1.15 A∘According to Bragg's equation. nλ=2d sinθ As. n=2,λ=1.00 A∘, θ=60∘, d=? ⇒d=1sin60∘=2√3=1.15A∘

The second order Bragg diffrction of $X - r a y s$ with $λ = 1.00 A^{\circ}$ from a set of parallel planes in a metal occurs at an angle $60^{\circ} .$ The distance between the scattering planes in the crystal is

The correct option is D $1.15 A^{\circ}$
According to Bragg's equation.
$n λ = 2 d sin θ$
As. $n = 2, λ = 1.00 A^{\circ}, θ = 60^{\circ}, d = ?$
$\Rightarrow d = \frac{1}{sin 60^{\circ}} = \frac{2}{\sqrt{3}} = 1.15 A^{\circ}$