Question

The second order Bragg's diffraction of rays with $\lambda$ = 1A from a set of parallel planes in a metal occurs at an angle of ${60}^{\circ }$ The distance between the scattering planes in the crystal is

• A. 0.575 Å
• B. 1.00 Å
• C. 2.00 Å
• D. 1.15 Å

Answer 1

The correct option is D 1.15 Å

$2dsin\theta =n\lambda or2\times d\times sin{60}^{\circ }=2\times 1\stackrel{\circ }{A}$
or, $sin\theta =n\lambda or2\times d\times 0.8660=2$
or, $d=1.15\stackrel{\circ }{A}(sin{60}^{\circ }=\frac{\sqrt{3}}{2}or0.8660)$