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Question

The secondary induced voltages of a LVDT, shown in the following figure, at null position are ¯¯¯¯¯V1=1.0V0°,¯¯¯¯¯V2=1.0V10° respectively. Then the null voltage of the LVDT is



A
0 V
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B
0.014V
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C
0.174 V
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D
2 V
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Solution

The correct option is C 0.174 V
The null voltage of the above shown LVDT is given by

Null voltage=¯¯¯¯¯V1¯¯¯¯¯V2

=1.001.010

=1(cos0+i sin10)1(cos10+i sin10)

=1(1+i0)1(0.9848+i0.1736)

=0.0152i0.1736

Magnitude of null voltage

=(0.0152)2+(0.1736)2

=0.03036=0.1742

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