the seet of values of x satiesfying (x^2 - x -1) (x^2 - x - 7) < -5 is (a,b) uniton (c,d) then a+b+c+d is equal to

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f (x) = \frac{x^{2} + x + 2}{x^{2} + x + 1} : x \in R

\frac{3 x^{3} + 5 x - 4}{(x^{2} - 1) (x^{2} - 4)} = \frac{A}{x + 1} + \frac{B}{x - 1} + \frac{C}{x + 2} + \frac{D}{x - 2}

A + B + C + D

\frac{1}{x^{4} + x^{2} + 1} = \frac{A x + B}{x^{2} + x + 1} + \frac{C x + D}{x^{2} - x + 1}

C + D =

Solveis equal to

(A) (B) (C) (D)

f (x) = \frac{x^{2} + x + 2}{x^{2} + x + 1}; x ϵ R

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