Question

The selection board of a team purchased 'xy' number of boots for the players. They again purchased 'yx' number of boots and distributed all of them to the players equally. If there were 11 players, then find the number of boots each of them received.

• A. (x + y)
• B. (x - y)
• C. 20(x + y)
• D. 11(x + y)

Answer 1

The correct option is A (x + y)

Given,
Selection board purchased xy = 10x + y boots for the players.
Then, they bought yx = 10y + x boots for the players
Number of players = 11

Now, total number of boots purchased
= 10x + y + 10y + x
= 11x + 11y
= 11 (x + y)
All the boots were distributed equally.
i.e, number of boots left after distributing it equally to the players, is 0.

$\Rightarrow \frac{11(x+y)}{Numberofplayers}=Numberofbootseachplayerreceived$

$\Rightarrow \frac{11(x+y)}{11}=x+y$

Therefore, the number of boots each player received is (x + y).