Question

The self inductance of a coil having 200 turns is 10mH.If current flowing through the coil is 4mA, the magnetic flux through each cross-section of the coil is;-

• A. $2\times {10}^{-4}Wb$
• B. $2\times {10}^{-7}Wb$
• C. $5\times {10}^{-4}Wb$
• D. $5\times {10}^{-7}Wb$

Answer 1

Answer: (B)

$2\times {10}^{-7}Wb$

Given,

Self-inductance $L=10mH$

Number of turns. $N=200turns$

Current, $I=4mA$

Magnetic Flux,$\varphi =\frac{LI}{N}=\frac{10\times {10}^{-3}\times 4\times {10}^{-3}}{200}=2\times {10}^{-7}Wb$