Question

The self inductance of a coil having 500 turns is 50 mH. The magnetic flux through the cross-sectional area of the coil while current through it is 8 mA is found to be

• A. $4\times {10}^{-4}Wb$
• B. $0.04Wb$
• C. $4\mu Wb$
• D. $40mWb$

Answer 1

Answer: (A)

$4\times {10}^{-4}Wb$

The magnetic flux through an inductor is the self inductance of coil times the current through it.

Thus $\varphi =LI$

$=50\times {10}^{-3}H\times 8\times {10}^{-3}A$

$=4\times {10}^{-4}Wb$