Question

The Selling Price Of $16$Spoons Is Equal To The Cost Price Of $15$ Spoons. Find The Loss Percent.

Answer 1

Let the cost price(CP) of $1$ spoon =$\mathrm{Rs}.1$

So, cost price(CP) of$16$spoons =$\mathrm{Rs}.16$

Selling price(SP) of $15$spoons =$\mathrm{Rs}.15$

As given in the question,

Selling price(SP) of $16$ spoons = Cost price(CP) of $15$ spoons

Loss = (CP) − (SP)

$$\begin{gathered} =(16-15) \\ =Rs.1 \end{gathered}$$

$\mathrm{The}\mathrm{Loss}\mathrm{percent}=\frac{\mathrm{loss}}{\mathrm{CP}}\times 100$

$$\begin{gathered} =\frac{1}{16}\times 100 \\ =6.25\% \end{gathered}$$

Hence, the loss percent is $6.25\%.$