Question

The sensitivity of a galvanometer of resistance 990 $\Omega$ is increased by 10 times. The shunt used is

• A. 100$\Omega$
• B. 120$\Omega$
• C. 110$\Omega$
• D. 50$\Omega$

Answer 1

Answer: (C)

110$\Omega$

Let shunt be x $\Omega$

= $=\frac{990\times x}{990+x}=Req$

$10\left(\frac{990x}{990+x}\right)=\left(990\right)$

= 9x=990

= x =110$\Omega$