Question

The seolution set of $x^2-5x+6\ge 2$ is

• A. $[2,3]$
• B. $(2,3)$
• C. $[1,4]$
• D. $(-\infty ,1]\cup [4,\infty )$

Answer 1

The correct option is D $(-\infty ,1]\cup [4,\infty )$

$x^2-5x+6\ge 2\Rightarrow x^2-5x+4\ge 0\Rightarrow (x-1)(x-4)\ge 0$


$\therefore x\in (-\infty ,1]\cup [4,\infty )$