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Method of Intervals

The seolution...

Question

The seolution set of $x^{2} - 5 x + 6 \geq 2$ is

A

[2, 3]

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B

(2, 3)

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C

[1, 4]

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D

(- \infty, 1] \cup [4, \infty)

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Solution

The correct option is D $(- \infty, 1] \cup [4, \infty)$
$x^{2} - 5 x + 6 \geq 2 \Rightarrow x^{2} - 5 x + 4 \geq 0 \Rightarrow (x - 1) (x - 4) \geq 0$

$∴ x \in (- \infty, 1] \cup [4, \infty)$

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Method of Intervals

Standard XII Mathematics

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