The separation between a node and the next antinode in a vibrating air column is 25 cm. If the speed of sound in air is 340 $m s^{- 1}$ , find the frequency of vibration of the air column

340 Hz

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240 Hz

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575 Hz

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670 Hz

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Solution

The correct option is A
340 Hz

v = 340 $\frac{m}{s}$

Distance between two nodes or antinodes

$\Rightarrow \frac{λ}{4} = 25 c m$

$\Rightarrow λ = 100 c m = 1 m$

$\Rightarrow \frac{v}{λ} = 340 H z$ .

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The separation between a node and the next antinode in a vibrating air column is 25 cm. If the speed of sound in air is 340 ms−1, find the frequency of vibration of the air column

The correct option is A 340 Hz v = 340ms Distance between two nodes or antinodes ⇒ λ4 = 25cm ⇒ λ = 100cm=1m ⇒ vλ=340Hz.

The separation between a node and the next antinode in a vibrating air column is 25 cm. If the speed of sound in air is 340 $m s^{- 1}$ , find the frequency of vibration of the air column

The correct option is A
340 Hz

v = 340 $\frac{m}{s}$

Distance between two nodes or antinodes

$\Rightarrow \frac{λ}{4} = 25 c m$

$\Rightarrow λ = 100 c m = 1 m$

$\Rightarrow \frac{v}{λ} = 340 H z$ .