The separation between the particles when their velocities become perpendicular to each other is

10 m

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50 m

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20 m

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None of these

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Solution

The correct option is B 50 m
The separation between them at a time t is given by,
$S = u_{1} t + u_{2} t$
From the above linked question we have,
$= (u_{1} + u_{2}) t = (u_{1} + u_{2}) . \frac{\sqrt{u_{1} u_{2}}}{g s i n θ}$
$= (25) \times \frac{\sqrt{100}}{10 \times 1} \times 2 = 50 m$

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The separation between the particles when their velocities become perpendicular to each other is

The correct option is B 50 mThe separation between them at a time t is given by,S=u1t+u2tFrom the above linked question we have,=(u1+u2)t=(u1+u2).√u1u2gsinθ=(25)×√10010×1×2=50m

The correct option is B 50 m
The separation between them at a time t is given by,
$S = u_{1} t + u_{2} t$
From the above linked question we have,
$= (u_{1} + u_{2}) t = (u_{1} + u_{2}) . \frac{\sqrt{u_{1} u_{2}}}{g s i n θ}$
$= (25) \times \frac{\sqrt{100}}{10 \times 1} \times 2 = 50 m$