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Question

The sequence logab,loga2b2,loga3b3.... is

A
a GP
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B
an AP
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C
a HP
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D
both a GP and a HP
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Solution

The correct option is A an AP
Given sequence is loga,loga2b2,loga3b3,...
Lets see the common difference between consecutive terms.
loga2b2logab=logab, loga3b3loga2b2=logab
Its difference is same. Thus it is an A.P.
It is an AP with general term tn=nlogab
So, option B is correct.

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