The series of natural numbers is written as follows: 1 2 3 4 5 6 7 8 9 ... ... ... ... ... ... Find the sum of the numbers in the nth row:
A
n3+1
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B
(2n)2−1
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C
n3+(n−1)3
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D
None of these
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Solution
The correct option is Cn3+(n−1)3 Go through options. Let us consider choice (c) forn=1,S1=(1)3+(1−1)3=1forn=2,S2=(2)3+(2−1)3=9forn=3,S3=(3)3+(3−1)3=35 Hence choice (c) is correct.