The set A -1-4-9-16-25- in set builder form is written as-A- A-x- x is the cube of a natural number B- A - x - x is a prime number C- A - x - x is the square of a natural number D- A - x - x is an even natural number

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Byju's Answer

Standard VII

Mathematics

Number Patterns/Relations

The set A =1,...

Question

The set A = {1,4,9,16,25---} in set builder form is written as:

A = {x:x is an even natural number}

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A ={x:x is the cube of a natural number}

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A = {x:x is a prime number}

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A = {x:x is the square of a natural number}

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Solution

The correct option is D
A = {x:x is the square of a natural number}

In set builder form, all the elements of a set possess a single common property which is not possessed by any element outside the set. Here, all the elements in the given set are square of a natural number.

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Similar questions

Taking the set of natural numbers as the universal set, write down the complements of the following sets:

(i) {x: x is an even natural number}

(ii) {x: x is an odd natural number}

(iii) {x: x is a positive multiple of 3}

(iv) {x: x is a prime number}

(v) {x: x is a natural number divisible by 3 and 5}

(vi) {x: x is a perfect square}

(vii) {x: x is perfect cube}

(viii) {x: x + 5 = 8}

(ix) {x: 2x + 5 = 9}

(x) {x: x ≥ 7}

(xi) {x: x ∈ N and 2x + 1 > 10}

Taking the set of natural numbers as the universal set, write down the complement of the following sets :

(i) {x : x is an even natural number}

(ii) {x : x is an odd natural number}

(iii) {x : x is a positive multiple of 3}

(iv) {x : x is a prime number}

(v) {x : x is a natural number divisible by 3 and 5}

(vi) {x : x is a perfect square}

(vii) {x : x is a perfect cube}

(viii) {x : x + 5 = 8}

(ix) {x : 2x + 5 = 9}

(x) {x : x $\geq$ 7}

(xi) {x : x $\in$ N and 2x + 1 > 10}

The set-builder representation of set $B = {1, 3, 5, 7, 9}$ is ______.

If A = {x: x is a natural number}, B ={x: x is an even natural number}

C = {x: x is an odd natural number} and D = {x: x is a prime number}, find

(i) A ∩ B

(ii) A ∩ C

(iii) A ∩ D

(iv) B ∩ C

(v) B ∩ D

(vi) C ∩ D

Q. If

A = {x : x

is a natural number

}, B = {x : x

is an even natural number

} C = {x : x

is an odd natural number

}

and

D = {x : x

is a prime number

},

find
(i)

A \cap B

(ii)

A \cap C

(iii)

A \cap D

(iv)

B \cap C

(v)

B \cap D

(vi)

C \cap D

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The set A = {1,4,9,16,25---} in set builder form is written as:

The correct option is D A = {x:x is the square of a natural number} In set builder form, all the elements of a set possess a single common property which is not possessed by any element outside the set. Here, all the elements in the given set are square of a natural number.

The correct option is D
A = {x:x is the square of a natural number}

In set builder form, all the elements of a set possess a single common property which is not possessed by any element outside the set. Here, all the elements in the given set are square of a natural number.