Question

The set $A=\{x:xϵR,x^2=16and2x=6\}$ equals

• A.
• B. {14, 3, 4}
• C. {3}
• D. {4}

Answer 1

The correct option is A

$x^2=16\Rightarrow x=\pm 4$

$2x=6\Rightarrow x=3$

There is no value of x which satisfies both the above equations.

Thus, $A=\varphi$.