The correct option is B {x:x=2n where n∈N such that n<6}
(a).{2,4,6,8}≠{2,4,6,8,10}
(b).{2,4,6,8,10}={2,4,6,8,10}
(c).{3,5,7}≠{2,4,6,8,10}
(d).{...−4,−2,0,2,4,6,8,10}≠{2,4,6,8,10}
Thus, Option b. has the correct "set builder" representation for the {2,4,6,8,10}