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Question

The set {78,89,910,1011,1112} expressed in set builder form is


A

{x:x=nn+1,nN,7<n<11}

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B

{x:x=7n7n+1,nN}

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C

{x:x=nn+1,nN}

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D

{x:x=nn+1,nN 7n11}

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Solution

The correct option is D

{x:x=nn+1,nN 7n11}


{78,89,910,1011,1112}=77+1,88+1,99+1,1010+1,1111+1 ={x:x=nn+1,nN 7n11} Hence (d)

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