The set 7-8- 8-9- 9-10- 10-11- 11-12 expressed in set builder form is x-x-n-n-1-n - N- 7 lt- n lt-11-x-x-n-n-1-n - N- 7 - n - 11-x-x-7n-7n-1-n - N-x-x-n-n-1-n - N-

The correct option is B x:x=n/n+1,n ∈ N 7 ≤ n ≤ 11 7/8, 8/9, 9/10, 10/11, 11/12=7/7+1, 8/8+1, 9/9+1, 10/10+1, 11/11+1 =x:x=n/n+1,n ∈ N 7 ≤ n ≤ 11 Hence (d) ...

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Byju's Answer

Standard VII

Mathematics

Set Builder Method

The set 7/8, ...

Question

The set { $\frac{7}{8}, \frac{8}{9}, \frac{9}{10}, \frac{10}{11}, \frac{11}{12}$ } expressed in set builder form is

{ $x : x = \frac{n}{n + 1}, n \in N, 7 < n < 11$ }

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{ $x : x = \frac{7 n}{7 n + 1}, n \in N$ }

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{ $x : x = \frac{n}{n + 1}, n \in N$ }

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{ $x : x = \frac{n}{n + 1}, n \in N 7 \leq n \leq 11$ }

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Solution

The correct option is D
{ $x : x = \frac{n}{n + 1}, n \in N 7 \leq n \leq 11$ }

{ $\frac{7}{8}, \frac{8}{9}, \frac{9}{10}, \frac{10}{11}, \frac{11}{12}$ }= $\frac{7}{7 + 1}, \frac{8}{8 + 1}, \frac{9}{9 + 1}, \frac{10}{10 + 1}, \frac{11}{11 + 1}$ ={ $x : x = \frac{n}{n + 1}, n \in N 7 \leq n \leq 11$ } Hence (d)

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Similar questions

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The set {78,89,910,1011,1112} expressed in set builder form is

The correct option is D {x:x=nn+1,n∈N 7≤n≤11} {78,89,910,1011,1112}=77+1,88+1,99+1,1010+1,1111+1 ={x:x=nn+1,n∈N 7≤n≤11} Hence (d)

The set { $\frac{7}{8}, \frac{8}{9}, \frac{9}{10}, \frac{10}{11}, \frac{11}{12}$ } expressed in set builder form is