wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The set of all x(π,π) satisfying |4sinx1|<5 is given by

A
(π10,3π10)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(π10,3π10)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(π10,3π10)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B (π10,3π10)
We are given the equation |4sinx1|<5
5<4sinx1<5
(514)<sinx<(5+14)
sinπ10<sinx<cosπ5
sin(π10)<sinx<sin(π2π5)
sin(π10)<sinx<sin(3π10)
x(π10,3π10)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ellipse and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon