The set of points in C satisfying the inequality ∣∣∣arg(z)−π2∣∣∣<π2 is
A
{z:Im(z)>0}
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B
{z:Im(z)<0}
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C
{z:Re(z)>0}
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D
{z:Re(z)<0}
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Solution
The correct option is A{z:Im(z)>0} Given that ∣∣∣arg(z)−π2∣∣∣<π2 ⇒−π2<arg(z)−π2<π2 ⇒0<arg(z)<π ⇒z lies in either first quadrant or second quadrant and hence Im(z)>0 ∴ the required set is {z:Im(z)>0}