The set of points of discontinuity of the function $f (x) = \frac{1}{x^{2} + x + 1}$ .

ϕ

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Solution

The correct option is A $ϕ$
$f (x) = \frac{1}{x^{2} + x + 1}$
If $x^{2} + x + 1 = 0$ it is discontinuous but $x^{2} + x + 1 = 0$ for $x = ω_{1}$ which is not real
Hence it is continuous at all points [set of points of discontinuous $= ϕ$ ).

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