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Byju's Answer
Standard XII
Mathematics
Graph of Quadratic Expression
The set of po...
Question
The set of points where the function
f
(
x
)
=
|
x
−
1
|
e
x
is differentiable is
A
R
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B
R
−
{
1
}
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C
R
−
{
−
1
}
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D
R
−
{
0
}
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Solution
The correct option is
B
R
−
{
1
}
From the graph we can see that the function is continuous everywhere in
R
but have a sharp corner at
x
=
1
.
So, it is not differentiable at
x
=
1
So, the function is differentiable in
R
−
{
1
}
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0
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Q.
The set of points where the function f(x) = |2x – 1| sin x is differentiable, is
(a) R
(b)
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Q.
The set of points, where the function
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Q.
The set of points where the function f (x) given by f (x) = |x − 3| cos x is differentiable, is
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