The set of real values of x satisfying -x-1-1-2- is

||x 1| 1|≤2 ⇒ 2≤|x 1| 1≤2 nbsp; ⇒ 1≤|x 1|≤3 ⇒ nbsp; 0 ≤|x 1|≤3 (∵ |x 1|≥0 ∀ x∈ℝ) ⇒ 3 ≤ x 1 ≤ 3 ⇒ 2≤ x≤4 ...

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Inequalities Involving Modulus Function

The set of re...

Question

The set of real values of $x$ satisfying $∣ ∣ | x - 1 | - 1 ∣ ∣ \leq 2,$ is

[2, 4]

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[- 2, 4]

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[- 4, - 2]

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[- 1, \infty)

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| | x - 1 | - 1 | \leq 1

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l o g_{\frac{1}{2}} (x^{2} - 6 x + 12) \geq - 2

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