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Question

The set of roots of the quadratic equation x28x+12=0 is

A
{3,6}
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B
{2,6}
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C
{2,8}
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D
{3,8}
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Solution

The correct option is B {2,6}
Given: x28x+12=0
Let α,β be the roots of the equation ax2+bx+c=0
α=b+D2a

& β=bD2a
D=b24ac is the discriminant of the equation.
Here, D=644(1)(12)=16
D=4
α=8+42×1=6 & β=842×1=2

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