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Method of Intervals

The set of th...

Question

The set of the solutions for $\frac{(x + 1) (x - 3)}{(x + 5)} < 0$ is

A

(- \infty, - 5) \cup (- 1, 3)

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B

(- \infty, - 5) \cup (- 1, \infty)

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C

(- 5, - 1) \cup (3, \infty)

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D

(- \infty, - 1) \cup (3, \infty)

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Solution

The correct option is A $(- \infty, - 5) \cup (- 1, 3)$
$\frac{(x + 1) (x - 3)}{(x + 5)} < 0$

$∴ x \in (- \infty, - 5) \cup (- 1, 3)$

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Method of Intervals

Standard XII Mathematics

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