The correct option is D (−∞,−43)∪(2,∞)
∵f′(x)=(4a−3)(1)+(a−7)cosx=(4a−3(a−7)+cosx)(a−7)f′(x)≠0
(for non existence of critical points)
4a−3a−7>1 or 4a−3(a−7)<−1(∵−1≤cosx≤1)⇒3a+4a−7>0 or5a−10a−7<0∴aϵ(−∞,−43)∪(7,∞) or aϵ(2,7)Hence,aϵ(−∞,−43)∪(2,∞)(∵at a=7,f′(x)≠0)