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Question

The set of values of a for which x2+ax+sin1(x24x+5)+cos1(x24x+5)=0 has at least one solution is

A
(,2π][2π,)
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B
(,2π)(2π,)
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C
R
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D
none of these
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Solution

The correct option is C (,2π)(2π,)
We have,
x2+ax+sin1(x24x+5)+cos1(x24x+5)=0x2+ax+π2=0

For at least one solution
x2+ax+sin1(x24x+5)+cos1(x24x+5)=0x2+ax+π2=0D0(a24.π2)0(a22π)0a22π(a+22π)(a22π)0++––––––––––––––––––––––––2π2πat(,2π)(2π,)

Option B is correct answer.

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