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Question

The set of values of 'c' so that the equations y=|x|+c and x2+y28|x|9=0 have no solution is


A

(,3)(3,)

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B

(3,3)

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C

(,52)(5(2),)

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D

524,

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Solution

The correct option is D

524,


Since y=|x|+c and x2+y28|x|9=0 both are symmetrically about y-axis for x>0, y=x+c.
Equation of tangent to circle x2+y28x9=0 parallel to y=x+c is y=(x4)+51+1
y=x+(524)
For no solution c>524
cϵ(524,)


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