The set of values of aϵR for which x2+i(a−1)x+5=0 will have a pair of conjugate complex roots is
A
R
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
{1}
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
{a|a2−2a+2|>0}
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B{1} x2+i(a−1)x+5=0 where a∈R Let α & β be the roots of the equation. Since the equation have pair of complex conjugate roots. ∴α=¯β&β=¯α Sum of the roots of the equation= α+β=−i(a−1) ...(1) By taking conjugate. ⇒¯α+¯β=i(a−1) ...(2) Substracting (1) & (2) ⇒α+β−¯α−¯β=−2i(a−1) ∴a=1 ...{ ∵α=¯β&β=¯α}