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Question

The set of values of λ such that the equation cosθ+cos2θ+λ=0 admits of a solution for θ is

A
[0,+)
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B
[0,98]
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C
[3,0]
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D
None of these
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Solution

The correct option is B [0,98]

cosθ+cos2θ+λ=0
cosθ+2cos2θ1+λ=0
2cos2θ+cosθ+(λ1)=0
cosθ=1±98λ4
We know,
98λ0
λ98
1cosθ1
41±98λ4
998λ
λ0
so,
[0,98]


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