The set of values of x for which tan 3x-tan 2x1-tan 3xtan 2x-1- is

The correct option is C nπ+π4, n∈ I According to given question, tan3x tan2x1+tan3xtan2x=1 ⇒ #160; tan(3x 2x)=1 ⇒ #160; tanx ...

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The set of va...

Question

The set of values of $x$ for which $\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1$ , is

ϕ

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\frac{π}{4}

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{

n π + \frac{π}{4}, n \in I

}

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{

2 n π + \frac{π}{4}, n \in I

}

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Similar questions

\frac{t a n 3 x - t a n 2 x}{1 + t a n 3 x t a n 2 x} = 1 \Rightarrow x = n π + \frac{π}{4}, n \in l

t a n x

x = n π + \frac{π}{2}, n \in l

\frac{tan 3 x - tan 2 x}{1 + tan 2 x tan 3 x} = 1

x = n π + \frac{π}{4}, \forall n \in I

tan x

x = n π + \frac{π}{2}, n \in I

x

\frac{tan 3 x - tan 2 x}{1 + tan 3 x \cdot tan 2 x} = 1

n \in Z

x

\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1

{n π + \frac{π}{4}, n \in l}

(1 + t a n x + {tan}^{2} x)

(1 - cot x + {cot}^{2} x)

x

e^{sin x} - e^{- s ˙ i n x} \neq 4

x

\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1 i s x = n π + \frac{π}{4}

tan x

\frac{π}{2}

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