The set of values of x- for which tan 3 x-tan 2 x-1-tan 3 x tan 2 x-1 is

The correct option is A ϕG.E.⇒ tan(3x 2x)=1 ⇒ tan x=1 ⇒ x = n π + π/4, n ϵ Z If x=n π+π/4 then tan 2x is not defined. ∴ There is no x such that tan 3x tan 2x/1 ...

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Standard XII

Mathematics

Trigonometric Ratios for Sum of Two Angles

The set of va...

Question

The set of values of x, for which $\frac{t a n 3 x - t a n 2 x}{1 + t a n 3 x t a n 2 x} = 1$ is

ϕ

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{\frac{π}{4}}

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{n π + \frac{π}{4} : n ϵ Z}

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{n π + \frac{π}{4} : n ϵ Z}

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Solution

The correct option is A $ϕ$
$G . E . \Rightarrow t a n (3 x - 2 x) = 1 \Rightarrow t a n x = 1 \Rightarrow x = n π + \frac{π}{4}, n ϵ Z$
$I f x = n π + \frac{π}{4}$ then tan 2x is not defined.
$∴$ There is no x such that $\frac{t a n 3 x - t a n 2 x}{1 + t a n 3 x . t a n 2 x} = 1$

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Similar questions

Q. Set of values for which

\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1

is true is

Q. The solution for

x

which satisfy the equation

\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1

Q. Solve :

\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1

Q. Solve

\frac{t a n 3 x - t a n 2 x}{1 + t a n 3 x t a n 2 x} = 1

Q.
I) The set of values of

x

for which

\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1

{n π + \frac{π}{4}, n \in l}

II) The expression

(1 + t a n x + {tan}^{2} x)

(1 - cot x + {cot}^{2} x)

is positive for all defined values
of

x

III)

e^{sin x} - e^{- s ˙ i n x} \neq 4

for any real values of

x

.
Which of the following is correct?

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The set of values of x, for which tan 3x−tan 2x1+tan 3x tan 2x=1 is

The correct option is A ϕG.E.⇒tan(3x−2x)=1⇒tan x=1⇒x=nπ+π4,nϵZ If x=nπ+π4 then tan 2x is not defined. ∴ There is no x such that tan 3x−tan 2x1+tan 3x.tan 2x=1

The set of values of x, for which $\frac{t a n 3 x - t a n 2 x}{1 + t a n 3 x t a n 2 x} = 1$ is

The correct option is A $ϕ$
$G . E . \Rightarrow t a n (3 x - 2 x) = 1 \Rightarrow t a n x = 1 \Rightarrow x = n π + \frac{π}{4}, n ϵ Z$
$I f x = n π + \frac{π}{4}$ then tan 2x is not defined.
$∴$ There is no x such that $\frac{t a n 3 x - t a n 2 x}{1 + t a n 3 x . t a n 2 x} = 1$