The set of values of x for which tan3x-tan2x-1-tan3xtan2x-1 is-

The correct option is C { nπ +π/4; n= 1, 2,3 ,.......} use>(tanA tanB/1+tanA>tanB)=tan(A B) ∴>>(tan3x tan2x/1+tan3x>tan2x)=1 & ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Trigonometric Ratios for Sum of Two Angles

The set of va...

Question

The set of values of x for which $\frac{t a n 3 x - t a n 2 x}{1 + t a n 3 x t a n 2 x} = 1$ is-

ϕ

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

{n π + \frac{π}{4}; n = 1, 2, 3, . . . . . . .}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

{2 n π + \frac{π}{4}}; n = 1, 2, 3, . . . . .

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

\frac{t a n 3 x - t a n 2 x}{1 + t a n 3 x t a n 2 x} = 1 \Rightarrow x = n π + \frac{π}{4}, n \in l

t a n x

x = n π + \frac{π}{2}, n \in l

x

\frac{tan 3 x - tan 2 x}{1 + tan 3 x \cdot tan 2 x} = 1

n \in Z

x

\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1

{n π + \frac{π}{4}, n \in l}

(1 + t a n x + {tan}^{2} x)

(1 - cot x + {cot}^{2} x)

x

e^{sin x} - e^{- s ˙ i n x} \neq 4

x

\frac{tan 3 x - tan 2 x}{1 + tan 2 x tan 3 x} = 1

x = n π + \frac{π}{4}, \forall n \in I

tan x

x = n π + \frac{π}{2}, n \in I

\frac{tan 3 x - tan 2 x}{1 + tan 3 x tan 2 x} = 1 i s x = n π + \frac{π}{4}

tan x

\frac{π}{2}

Join BYJU'S Learning Program