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Question

The set of values of x for which the inequalities x23x10<0 and 10xx216>0 hold simultaneously, is

A
(2,5)
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B
(2,8)
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C
(2,8)
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D
(2,5)
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Solution

The correct option is B (2,5)
We have,
x23x10<0
(x5)(x+2)<0
2<x<5
Also,
10xx216>0
x210x+16<0
(x2)(x8)<0
Hence, 2<x<8
The common set for x is (2,5).

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