The set of values of x for which the inequality (3x−1)(4x−16)(x−5)<0 is
Let the given expression be E:(3x−1)(4x−16)(x−5)<0
3x−1=0⇒x=0
4x−16=0⇒x=2
x−5=0⇒x=5
Use wavy curve method
Sign scheme of E is shown below.
From above figure, we have E<0 for x∈(−∞,0)∪(2,5)
Hence the correct answer is A.