The set of values of x satisfying the inequation (2−π2)(cot−1x−3)+tan−1x(cot−1x−3)>0 is
A
(cot2,cot3)
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B
(−∞,cot2)
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C
(cot3,cot2)
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D
(cot3,∞)
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Solution
The correct option is C(cot3,cot2) Given : (2−π2)(cot−1x−3)+tan−1x(cot−1x−3)>0 ⇒(cot−1x−3)[2−(π2−tan−1x)]>0⇒(cot−1x−3)(2−cot−1x)>0(∵tan−1x+cot−1x=π2)⇒(cot−1x−3)(cot−1x−2)<0⇒cot−1x∈(2,3)
Since cot−1x is a decreasing function, so x∈(cot3,cot2)